Odds Vs Number of players
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Odds Vs Number of players
Does anyone know how the number of players affects the odds of winning?
I can calculate the odds of winning based on what is in my hand and what is on the board, but this is for a two player game.
I was wondering if it's possible to easily calculate the odds for games with the same cards on the table and in my hand, but with a different number of players.
E.g. if my odds of winning are 10:1 with two players, would the odds be 20:1 with three players? I suspect that it's more complex than that, but I'm hoping not.
I can calculate the odds of winning based on what is in my hand and what is on the board, but this is for a two player game.
I was wondering if it's possible to easily calculate the odds for games with the same cards on the table and in my hand, but with a different number of players.
E.g. if my odds of winning are 10:1 with two players, would the odds be 20:1 with three players? I suspect that it's more complex than that, but I'm hoping not.
- izb
- Posts: 1
- Joined: Sun Jul 18, 2004 10:40 am GMT
Re: Odds Vs Number of players
izb wrote:
E.g. if my odds of winning are 10:1 with two players, would the odds be 20:1 with three players? I suspect that it's more complex than that, but I'm hoping not.
I totally agree with that statement.
- vegasholdem
- Posts: 139
- Joined: Mon Aug 16, 2004 4:30 pm GMT
- Location: las vegas
odds formulas
The winning odds for your hand are the same, no matter how many opponents you have (the information - seen cards - is the same).
The parameter n= number of your opponents is involved when calculating your opponents winning odds. For example, for "at least one opponent" type events: the probability formula for at least one opponent to can achieve a specific card formation (or many) is something like that:
P = n*P(one opponent can achieve that formation) - C(n,2)*P(two opponents can achieve that formation) + C(n,3)*P(three opponents...) - ... and so on.
For all odds and all math behind the game, see www.probability.go.ro/page8.html
The parameter n= number of your opponents is involved when calculating your opponents winning odds. For example, for "at least one opponent" type events: the probability formula for at least one opponent to can achieve a specific card formation (or many) is something like that:
P = n*P(one opponent can achieve that formation) - C(n,2)*P(two opponents can achieve that formation) + C(n,3)*P(three opponents...) - ... and so on.
For all odds and all math behind the game, see www.probability.go.ro/page8.html
- infarom
- Posts: 4
- Joined: Wed Jul 28, 2004 11:46 am GMT
- Location: Craiova, RO
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