Odds Question
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Odds Question
I stuck this here so it would get noticed, I post on another forum and there is a huge discussion about this and what the right way of finding the answer is.
The Question is, 4 people sit at a table and are dealt all of the 52 cards, what is the chance that one of them has a pile of cards with a matching suit?
My theory was that you find the chance of getting a certain suit on each deal and then multiply all those chances together and then multiply it by 4 in the end (any 4 of the players can get this suited pile so 4x the chance)
so.. 12/51 = .235
11/50 = ....
and then you multiply all those fraction answers together to find the probability.
Anyone have any input here?
The Question is, 4 people sit at a table and are dealt all of the 52 cards, what is the chance that one of them has a pile of cards with a matching suit?
My theory was that you find the chance of getting a certain suit on each deal and then multiply all those chances together and then multiply it by 4 in the end (any 4 of the players can get this suited pile so 4x the chance)
so.. 12/51 = .235
11/50 = ....
and then you multiply all those fraction answers together to find the probability.
Anyone have any input here?
- Ryan231
- Posts: 169
- Joined: Fri Sep 30, 2005 10:22 pm GMT
My theory was that you find the chance of getting a certain suit on each deal and then multiply all those chances together
I think thats it
find the chance of getting one particular suit per card then multiply that chance with the amount of cards dealt? or something like that, maybe i shouldve payed more attention in mathematics class when we discussed this
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kingetje - Posts: 1749
- Joined: Wed Feb 15, 2006 12:44 pm GMT
- Location: Netherlands
That's right.
If it was a certain suit though you'd start with 13/52 x 12/51 x 11/50...
But if you just wanted to know the chance that they all are of the same suit, doesn't matter which, you'd start with 12/51 x 11/50 x 10x49...
Moving this from General Chat to Odds & Probability.
If it was a certain suit though you'd start with 13/52 x 12/51 x 11/50...
But if you just wanted to know the chance that they all are of the same suit, doesn't matter which, you'd start with 12/51 x 11/50 x 10x49...
Moving this from General Chat to Odds & Probability.
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Adamm - Admin
- Posts: 758
- Joined: Tue Jan 21, 2003 6:03 am GMT
- Location: Pittsburgh
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