Split Pot Multiple subpots with odd chips

[marc55alex]

i.e. Total Pot $8000, mainpot $925,subpots $5075, $1925, $75

Smallest Chip $5, each pot has an odd chip.

Two of the big chip stacks have, for example Broadway, for the winning hands.

from "Robert Rules of Poker"
An odd chip is broken down to the smallest unit used in the game.
No player can receive more than one odd chip.
button game, the first hand clockwise from the button gets the odd chip.
All side pots and the main pot are split as separate pots, not mixed together

I'm writing a program and need a rule for the computer to follow.

I would think that each of the two winners gets $4000, splitting the total pot, but this mixes the main and subpots together. If they are split as seperate pots, not mixed together, then one player gets more than one odd chip. In this case, 4 odd pots times $5, $4020 worst position/$3080 best position.

Do you treat the smaller All-Ins that don't win like folded chips making the $8000 become the pot that the same two players split, or do the same two players split $925, then $5075, then $1925, and finally $75?

If they must split each pot seperately, and if my example had an odd numbered total amount and an odd number of pots would they alternate the odd chips?

[HalfSugar]

It's quite tricky from the point of view of writing a program. In real life, if the two biggest stacks chop such a pot, you'd just chop the total and allocate any odd chip left of the dealer.

Perhaps you could write it so that once the winner(s) of the pot is determined, all pots that he/they straddle are combined and split appropriately. Any surplus chips (eg side pots not covered by the winner) are separately chopped between the eligible players.

Chopping multiple pots in the right ratio is not a very elegant way to allocate the chips because of the residuals as you say. Alternating the residual chips alternately could work but if there are more than two players chopping pots (rare but possible) it might work quite badly.

I really think you need to find a way to amalgamate all pots that the winner(s) cover(s) and chop those first as an aggregate chip count.

[marc55alex]

I set up an array that tracked who was recieved odd chips. When everyone in a split has gotten an odd chip then it goes back to worst position and so on. Functionally it works the same as chopping the total, at least in the tests I've thrown at it. So far it works the way I expect it to.

I hoping someone is familiar with an official rule.

[HalfSugar]

The official rule is to create the largest pot possible for the winner(s) and award it. Any additional chips are chopped between eligible players with odd chips going left of the dealer button. This is repeated for all side pots as appropriate.

What is not right is to chop the main pot (plus any side pots as necessary) into smaller chunks once it has been created. Whatever action has gone before is irrelevant - the winning player(s) straddle(s) a certain number of chips once the hand has been dealt.

[marc55alex]

The official rule is to create the largest pot possible for the winner(s) and award it.

Perhaps you're having a bad week.

TexasHoldem-Poker.com's "Official" Texas Holdem Rules...
Split Pots, Side Pots, and going All-in...
14. Each side pot will be split as a separate pot. They will not be mixed together before they are split.

It's obvious that I'm wasting my time here. I can imagine if you've only played Holdem you could think that way, but anyone who has played at least 10 hands of Omaha/8, would know you're not on the right page.

Pots are paid out seperately, never combined into a large pot.

Since Omaha/8 has the sames rule for split pots, it's was an easy to search through some hand histories for something similar to my question. Since what I'm doing is the same as the online poker sites I'm not too worried.

[HalfSugar]

First of all, what a douchebag attitude you have. Second of all, that is definitely the wrong ruling above, I don't care what Robert's Rules state.

Let's say we are at a ten-handed table with a ton of short stacks all with different chip counts and two big stacks covering everyone. If everyone goes all-in and the two big stacks share the winning hand, if every side pot has an odd chip, there is no way that the big stack to the left of the dealer gets 8 odd chips.

In that scenario, the chips would be shoved into a big pile, counted and halved. Even if that really is 'officially' wrong, there is no card room in the world that would chop 8 side pots and give 8 odd chips to one player.

[jeffonline]

Whats the rake?