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chicoelnino
Joined: 13 May 2005 Posts: 28
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Posted: Tue May 24, 2005 7:42 am GMT Post subject: Figuring out pot odds! |
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I not really well versed on the whole pot odds thing. Its something that I really want to be able to understand, but I can't say I even know the basics.
Could someone point me in the right direction of either a website or a book that explains pot odds in laymans terms???? /b |
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PuckJunkieNY

Joined: 08 Jan 2004 Posts: 762 Location: Rochester, NY
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Posted: Tue May 24, 2005 8:01 am GMT Post subject: Re: Figuring out pot odds! |
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| chicoelnino wrote: | I not really well versed on the whole pot odds thing. Its something that I really want to be able to understand, but I can't say I even know the basics.
Could someone point me in the right direction of either a website or a book that explains pot odds in laymans terms???? /b |
Have you explored the rest of this site?
Start here: http://www.texasholdem-poker.com/odds.php _________________ "Cards are war, in disguise of a sport."
-Charles Lamb, "Essays of Elia" (1832) |
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suitedaces84

Joined: 12 Dec 2004 Posts: 2378 Location: A van down by the river
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Posted: Wed May 25, 2005 3:08 pm GMT Post subject: |
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Here it is, unfortunatly, I don't think it's in "laymans terms". The first thing is to learn exactly what odds are.
Odds vs Probablility
Odds
-bad:good
Probability
-good in total
total = bad + good
so if my odds are X:Y the probability will be Y in (X+Y)
so 3:1 is the same as 1 in 4
Converting a % to odds
if you have a x% chance of winning your odds are
100-x:x
so if you have a 30% chance a winning the odds are 70:30
70:30 can be simplified to 2.3:1
Converting odds to a %
If your odds are X:Y you will have a Y/(X+Y)*100% chance of winning.
How you can actually use this
If the pot is $13 on the river and your oppoent bets $10 how sure do you have to be that you're beat in order to fold?
The odds are 2.3:1 so if you're more than 30% sure you're beat you should fold.
Let's say I'm 40% sure I'm beat and I call. I lose 60% of the time costing me .6*$10 = $6. However I'll win 40% of the time gaining me .6*$23 = $9.2.
How you can apply this to draws
If I have flush draw on the turn with a pot of $20 and an incoming bet of $7 and I want to determine if I have good pot odds I use the same logic as above. There are 46 cards in the deck and 9 are outs so the odds are 37 bad cards. So my odds are 37:9, this is about 4:1. So if the pot is four times the incoming bet I have good pot odds. In this case I'm 4:1 on my draw and 3.9:1 on my draw. So my pot odds are not good. Of course it's still an easy call because pot odds neglect any money I can win on future streets. So as long as I can get him to call a bet of at least $1 on the river when my flush hits I would be correct to call due to implied odds.
It's all much easier than I made it sound. Just memorize the basic odds below.
Flush--4:1
Open-ended straight--4.5:1
Gutshot straight--10.5:1
Before calling with a draw ask yourself: will I profit at least (appropiate odds based on draw) times the incoming bet?
One more thing to consider, drawing dead. If you've got a gutshot, there are 2 on the board four callers ahead of you it's likely that you have three outs not four...just look for things like that. _________________
| Muck wrote: | | I'd really like to rail some of you guys. |
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Geno King Moderator

Joined: 20 Jan 2003 Posts: 5348 Location: Surrey, UK
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Posted: Wed May 25, 2005 3:20 pm GMT Post subject: |
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I've moved this into the Odds & Probability forum. No doubt there is even more useful stuff in there for you  _________________ Guess what? I got a fever, and the only prescription, is more cowbell! |
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Hank

Joined: 28 Oct 2003 Posts: 53 Location: Sacramento,CA
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Posted: Wed May 25, 2005 5:32 pm GMT Post subject: |
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Nice succinct article on odds and probability.
Thanks suitedaces84!! |
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JackKingOff

Joined: 18 Feb 2006 Posts: 334 Location: Toronto
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Posted: Mon Apr 10, 2006 11:31 pm GMT Post subject: |
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ok... i just have a question... i am pretty sure what your doing is fine... however, ive seen a lot of articles or sites say to calculate pot odds u g2 find ur % of hitting ur draw... and to do this you multiply by 2 and then add 1 so basically for a flush draw ud have 19% chance to hit... or i dont know... ive been using that all along... would ur way be better? _________________ Eating this pizza is like having sex with a fat prostitute.
Pokerstars: Lapchong
Full Tilt: Lapchong |
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Geno King Moderator

Joined: 20 Jan 2003 Posts: 5348 Location: Surrey, UK
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Posted: Tue Apr 11, 2006 2:20 am GMT Post subject: |
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A quick and dirty calculation to find the % of you hitting your draw is:
On the flop, you take your number of outs and multiply by 4.
On the turn, you take your number of outs and multiply by 2.
Flush draw with 9 outs is therefore about 36% (about 1 in 3 or 2 to 1) on the flop, 18% (about 1 in 6 or 5 to 1) on the turn. _________________ Guess what? I got a fever, and the only prescription, is more cowbell! |
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jbark
Joined: 12 May 2006 Posts: 53 Location: Michigan
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Posted: Mon May 15, 2006 12:46 pm GMT Post subject: |
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I just ran across this post while reading and learning a bit about poker. but i think there is a typo in sutiedAces reply above where he wrote: | Quote: | How you can actually use this
If the pot is $13 on the river and your oppoent bets $10 how sure do you have to be that you're beat in order to fold?
The odds are 2.3:1 so if you're more than 30% sure you're beat you should fold.
Let's say I'm 40% sure I'm beat and I call. I lose 60% of the time costing me .6*$10 = $6. However I'll win 40% of the time gaining me .6*$23 = $9.2. |
i believe that the last line should read: "...gaining me .4*$23 = $9.2"
Now, i'm not claiming any great poker knowledge here because i don't have it but i think i would present this a little differently to make the example more clear. Like this:
How you can actually use this
If the pot is $13 on the river and your oppoent bets $10 how sure do you have to be that you're beat in order to fold?
The odds are 2.3:1 so if you're more than 30% sure you're beat you should fold.
Let's say I'm 40% sure I'm beat and I call. I lose 60% of the time costing me .6*$10 = $6. However I'll win 40% of the time gaining me .4*$23 = $9.2, so my expected value on the $10 bet is $9.2 - $6 = $3.2.
Another way of interpreting expected value is this: if i bet ten dollars in this situation i should expect to loose $10 - $3.2 = $6.8 dollars.
cheers
jerry |
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