What's the probability of this?

[FirebirdGM]

I'm just curious what the odds of both players in a heads-up game getting pocket aces is. Then, the probability of that happening the very next hand. I saw this in a Tiger Gaming tournament I was in [Which gives me more reason to believe that it's rigged..].

I'm not 100% sure, but this is what I tried:

4/52 * 3/51 * 2/50 * 1/49

Which equals something like .000369%.

Not sure if I'm right though.

[xDiamond_CutteRx]

As long as there are only two players, yes, that should be correct.

[Adamm]

This is one of my pet peeves.
You math is correct, but assumes that it happens on one particular hand. Many hands are actually dealt. I think a more fair way to analyze it would be "what are the chances that the other guy will have aces when I get aces?"
So it'd be 2/(50x49) or 1 in 1225 or .08% or so.