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Why is JTs better than QJs?

Analysis of specific hands and general game theory
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7 posts • Page 1 of 1

Why is JTs better than QJs?

Postby Matt T » Fri Mar 12, 2004 2:55 pm GMT

Is it because the extra straight (and straight-flush) possibility outweighs the fact that the Q is an overcard to a T? TIA!
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Postby littleogre » Fri Mar 12, 2004 3:13 pm GMT

More str8 possibilities.
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Postby ORGrinder » Fri Mar 12, 2004 4:22 pm GMT

isn't it all based on the total number of outs that are possible. the JT must have more possibilities to make a hand more powerful than the QJ on the flop...
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Postby UnluckyKyle » Fri Mar 12, 2004 9:37 pm GMT

i'll side with littleogre on this one, and here's why.

with a QJ you can only make these str8's

AKQJT
KQJT9
QJT98

whereas with the JT you can make:

AKQJT
KQJT9
QJT98
JT987

now, im not sure of the gap between which is better or not, but the JT has a 33% higher chance of making a straight than the QJ.
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Postby Matt T » Mon Mar 15, 2004 8:34 am GMT

I also just discovered that all 4 straights with the JT are the nuts (provided your J or T wasn't counterfeited). So that 'extra' straight is a very good one.
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Postby thepheonix » Wed Mar 17, 2004 12:12 am GMT

Um.... I am a little confused on that last statement. Wouldn't that same statement apply to the straights with QJ???? I understand the rest of the concepts but not that one about the nut straights.
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Postby Matt T » Wed Mar 17, 2004 8:49 am GMT

I wasn't very clear. The QJ straights would all be the nuts, but there's only three straights. The JT has four and they are all the nuts. The T9 also has four but the 9TJQK is NOT the nuts. AT beats it. JT is the only combo that has four straights AND all of them are the nuts.
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